Q7 / 75 · JEE Main 2025 (2 Apr Shift 1) · Chemistry
A molecule with the formula \(\mathrm{AX}_4 \mathrm{Y}\) has all it's elements from p-block. Element A is rarest, monoatomic, non-radioactive from its group and has the lowest ionization enthalpy value among A, X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is :
- Correct answerASquare pyramidal
- BOctahedral
- CPentagonal planar
- DTrigonal bipyramidal
Solution
Given A is rarest, monoatomic, non-radioactive p-block element and form \(\mathrm{AX}_4 \mathrm{Y}\) type of molecule.
\(\therefore\) It is concluded that it is Xe
It is given the electronegativity of A is less than X & Y
It is given the electronegativity of \(\mathrm{X} ~\&~ \mathrm{Y}\) is highest and second highest respectively among all element.
\(\therefore \mathrm{X} ~\&~ \mathrm{Y}\) are \(\mathrm{F} ~\&~ \mathrm{O}\)
\(\therefore\) Compound is consider as \(\mathrm{XeOF}_4\) with square pyramidal shape.
\(\therefore\) It is concluded that it is Xe
It is given the electronegativity of A is less than X & Y
It is given the electronegativity of \(\mathrm{X} ~\&~ \mathrm{Y}\) is highest and second highest respectively among all element.
\(\therefore \mathrm{X} ~\&~ \mathrm{Y}\) are \(\mathrm{F} ~\&~ \mathrm{O}\)
\(\therefore\) Compound is consider as \(\mathrm{XeOF}_4\) with square pyramidal shape.
Hence, the correct answer is option: 'A'.