A molecule $(X)$ has (i) four sigma bonds formed by the overlap of $s p^2$ and $s$ orbitals (ii) one sigma bond formed by $s p^2$ and $s p^2$ orbitals and (iii) one $\pi$ bond formed by $p_x$ and $p_z$ orbitals. Which of the following is $X$ ?

• A

  $\mathrm{C}_2 \mathrm{H}_6$
• B

  $\mathrm{C}_2 \mathrm{H}_3 \mathrm{Cl}$
• C

  $\mathrm{C}_2 \mathrm{H}_2 \mathrm{Cl}_2$
• Correct answer
  D

  $\mathrm{C}_2 \mathrm{H}_4$

Solution

Structure of $\mathrm{C}_2 \mathrm{H}_4$ is :


So, the compound $(X)$ is $\mathrm{C}_2 \mathrm{H}_4$.

Hence, the correct answer is option: 'D'.