Q74 / 90 · JEE Main 2021 (31 Aug Shift 2) · Physics

A mixture of hydrogen and oxygen has volume 500 cm3, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be:

  • Correct answer
    A
    16 : 3
  • B
    3 : 8
  • C
    8 : 3
  • D
    3 : 16

Solution

A number of moles of, O2=m132, the number of moles of, H2=m22. Using the ideal gas equation, PV=m132+m22253×300, 
400×103×500×10-6=m132+m2225×100⇒2×102=m1m2×132+12m2×25×100
⇒225=m1m2×132+12m2  ...(1)   
⇒m1+m2=0.76
⇒m21+m1m2=76100   ...(2) 
(1) divided by (2) ; m1m2×132+12m1m2+1=225×10076
Let assume, 
⇒m1m2=x⇒x+1632x+1=876⇒ 76x+76×16=8×32x+8×32⇒76x+1216=256x+256
960=180x⇒x=9618=163

Hence, the correct answer is option: 'A'.

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