A metallic element exists in cubic lattice. Each edge of unit cell is $\text{4}\stackrel{\text{o}}{\text{A}}$ The density of metal is $\text{6}\text{.25}\text{g}{\text{/m}}^{\text{3}}\text{.}$ How many unit cells will be present in $\text{100}\text{g}$ of metal?

• A

  $1\times 10^{22}$
• Correct answer
  B

  $2.5\times 10^{29}$
• C

  $5\times 10^{23}$
• D

  $2\times 10^{23}$

Hence, the correct answer is option: 'B'.