A metal surface is exposed to 500 nm radiation. The threshold frequency of the metal for photoelectric current is 4.3×10^14 Hz. The velocity of…

Question

A metal surface is exposed to 500 nm radiation. The threshold frequency of the metal for photoelectric current is 4.3×10^14 Hz. The velocity of ejected electron is ___×10^5 ms^(-1) (Nearest integer) Use:h=6.63×10^(-34)Js,m_e=9.0×10^(-31) kg

MARKS Content Team · Accepted Answer

Correct answer: 5. λ=500 nm→v=C/(λ)=(3×10^8)/(500×10^(-9))=6×10^14 Hz v_0=4.3×10^14 Hz For photo electric effect, hv=hv_0+KE KE=hv-hv_0=hv-v_0=6.6×10^(-34)6×10^14-4.3×10^14 =6.6×1.7×10^(-20) J K.E. =1/2mv^2;v=√(2×K·Em) V=√(2×6.6×1.7×10^(-20)9.1×10^(-31))=√(24.65×10^10)=5×10^5 m/s

A metal surface is exposed to $500 nm$ radiation. The threshold frequency of the metal for photoelectric current is $4.3 \times 10^{14} Hz$ . The velocity of ejected electron is $___\times 10^{5} {ms}^{- 1}$ (Nearest integer)
$[Use : h = 6.63 \times 10^{- 34} Js, m_{e} = 9.0 \times 10^{- 31} kg]$

Solution

Relevant Questions

A metal surface is exposed to 500 nm radiation. The threshold frequency of the metal for photoelectric current is 4.3×1014 Hz. The velocity of ejected electron is ___×105 ms-1 (Nearest integer)Use:h=6.63×10-34Js,me=9.0×10-31 kg

Solution

Relevant Questions

A metal surface is exposed to $500 nm$ radiation. The threshold frequency of the metal for photoelectric current is $4.3 \times 10^{14} Hz$ . The velocity of ejected electron is $___\times 10^{5} {ms}^{- 1}$ (Nearest integer)
$[Use : h = 6.63 \times 10^{- 34} Js, m_{e} = 9.0 \times 10^{- 31} kg]$