Q164 / 225 · JEE Main 2005 · Physics
A mass ' $m$ ' moves with a velocity $v$ and collides inelastically with another identical mass. After collision the $1^{\text {st }}$ mass moves with velocity $v / \sqrt{3}$ in a direction perpendicular to the initial direction of motion. Find the speed of the $2^{\text {nd }}$ mass after collision


- Av
- B$\sqrt{3} v$
- Correct answerC$2 v / \sqrt{3}$
- D$v / \sqrt{3}$
Solution

$m v=m v_1 \cos \theta$ $0=\frac{m v}{\sqrt{3}}-m v_1 \sin \theta$ $\therefore v_1=\frac{2}{\sqrt{3}} v$
Hence, the correct answer is option: 'C'.