Q66 / 90 · JEE Main 2023 (06 Apr Shift 1) · Physics

A mass m is attached to two springs as shown in figure. The spring constants of two springs are K1 and K2. For the frictionless surface, the time period of oscillation of mass m is

Figure

  • Correct answer
    A
    2πm K1+K2
  • B
    12πK1-K2m
  • C
    2πm K1-K2
  • D
    12πK1+K2m

Solution

Figure

For the given combination, if the block is displaced towards right, elongation in one spring will be equal to the compression in other and the direction of force due to both spring will be the same and restoring in nature. Hence, both springs are effectively in parallel combination.

Therefore,

⇒Keff=K1+K2 and

⇒T=2πmKeff=2πmK1+K2

Hence, the correct answer is option: 'A'.

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