Q162 / 180 · COMEDK 2015 · Physics
A $2 \mathrm{~kg}$ mass lying on a table is displaced in the horizontal direction through $50 \mathrm{~cm}$. The work done by the normal reaction will be
- A$10 \mathrm{~J}$
- Correct answerB0
- C$100 \mathrm{erg}$
- D$100 \mathrm{~J}$
Solution
Since, displacement on the body of mass $2 \mathrm{~kg}$ is in the horizontal direction while normal reaction acts on the body in perpendicular to the displacement.
Hence, $\quad \theta=0$
$\therefore$ Work done, $W=F s \cos 90^{\circ}=0$
Hence, the correct answer is option: 'B'.