Q145 / 180 · COMEDK 2013 · Physics

A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is $340 \mathrm{~ms}^{-1}$, then the distance between the cliffs is

  • A
    $680 \mathrm{~m}$
  • B
    $1700 \mathrm{~m}$
  • Correct answer
    C
    $340 \mathrm{~m}$
  • D
    $1620 \mathrm{~m}$

Solution

Let $x$ be the distance between a cliff and man, then time taken by the echo, $$ \begin{aligned} t &=\frac{2 x}{v}=1 \\ \Rightarrow \quad x &=\frac{v}{2}=\frac{340}{2}=170 \mathrm{~m} \end{aligned} $$ (given) $\therefore$ Distance between two cliffs $$ =2 x=2 \times 170=340 \mathrm{~m} $$

Hence, the correct answer is option: 'C'.

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