Q6 / 200 · MHT CET - Medical 2026 (25 April Shift 1) · Biology
A man, homozygous dominant for widows peak (WW), marries a woman with straight hairline homozygous recessive (ww). How many of their off springs will inherit straight hair line?
- A$100\ \%$
- B$50\ \%$
- C$25\ \%$
- Correct answerD$0\ \%$
Solution
The genotype of the man is $WW$ (homozygous dominant for widow's peak).
The genotype of the woman is $ww$ (homozygous recessive for straight hairline).
A cross between the parents ($WW \times ww$) will produce offspring that all have the genotype $Ww$ (heterozygous).
Since the allele for widow's peak ($W$) is dominant over the allele for straight hairline ($w$), all offspring will exhibit the widow's peak phenotype.
Therefore, the percentage of offspring inheriting a straight hairline is $0\ \%$.
Answer: $0\ \%$
The genotype of the woman is $ww$ (homozygous recessive for straight hairline).
A cross between the parents ($WW \times ww$) will produce offspring that all have the genotype $Ww$ (heterozygous).
Since the allele for widow's peak ($W$) is dominant over the allele for straight hairline ($w$), all offspring will exhibit the widow's peak phenotype.
Therefore, the percentage of offspring inheriting a straight hairline is $0\ \%$.
Answer: $0\ \%$
Hence, the correct answer is option: 'D'.