A magnetic needle of negligible breadth and thickness compared to its length, oscillates in a horizontal plane with a period T. The period of…

Question

A magnetic needle of negligible breadth and thickness compared to its length, oscillates in a horizontal plane with a period T. The period of oscillation of each part obtained on breaking the magnet into n equal parts and perpendicular to the length is

MARKS Content Team · Accepted Answer

Correct answer: (B) T/n. T=2π√IMB on breaking n equal parts perpendicular to length I′=1/12 m/n l^n2 of each part I′=I/(n^3), M′=M/n (T^(′))/T=√(I^(′)M^(′)×MI)=√(1n^3 ×n)=1/n⇒ T^(′)=T/n

A magnetic needle of negligible breadth and thickness compared to its length, oscillates in a horizontal plane with a period $T$ . The period of oscillation of each part obtained on breaking the magnet into $n$ equal parts and perpendicular to the length is

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