Q95 / 100 · BITSAT 2023 (Memory Based Paper 1) · Physics
A $100 \mathrm{~m}$ long wire having cross-sectional area $6.25 \times 10^{-4} \mathrm{~m}^2$ and Young's modulus is $10^{10}$ $\mathrm{Nm}^{-2}$ is subjected to a load of $250 \mathrm{~N}$, then the elongation in the wire will be :
- A$6.25 \times 10^{-3} \mathrm{~m}$
- B$4 \times 10^{-4} \mathrm{~m}$
- C$6.25 \times 10^{-6} \mathrm{~m}$
- Correct answerD$4 \times 10^{-3} \mathrm{~m}$
Solution
$\Delta \ell=\frac{F \ell}{Y A}=\frac{250 \times 100}{10^{10} \times 6.25 \times 10^{-4}}=40 \times 10^{-4} \mathrm{~m}$
$=4 \times 10^{-3} \mathrm{~m}$
$=4 \times 10^{-3} \mathrm{~m}$
Hence, the correct answer is option: 'D'.