Q70 / 90 · JEE Main 2022 (25 Jun Shift 1) · Physics

A long straight wire with a circular cross-section having radius R, is carrying a steady current I. The current I is uniformly distributed across this cross-section. Then the variation of magnetic field due to current I with distance rr<R from its centre will be 

  • Correct answer
    A
    B∝r
  • B
    B∝1r
  • C
    B∝r2
  • D
    B∝1r2

Solution

Using Ampere's law and noting that the steady current is uniformly distributed over the cross-section of the cylindrical wire.

B=μ0Ir2πR2,   r≤Rμ0I2πr,   r>R

Thus, magnetic field B∝r from the centre for r<R.

Hence, the correct answer is option: 'A'.

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