Q176 / 180 · KCET 2022 · Physics
A long solenoid has 500 turns, when a current of $2 \mathrm{~A}$ is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4 \times 10^{-3} \mathrm{~Wb}$, then selfinduction of the solenoid is
- A$2.5 \mathrm{H}$
- B$2.0 \mathrm{H}$
- Correct answerC$1.0 \mathrm{H}$
- D$4.0 \mathrm{H}$
Solution
Given, number of turns in the solenoid,
$$
N=500
$$
Current, $I=2 \mathrm{~A}$
Magnetic flux, $\phi=4 \times 10^{-3} \mathrm{~Wb}$
Self-inductance of coil,
$$
L=\frac{N \phi}{I}=\frac{500 \times 4 \times 10^{-3}}{2}=1 \mathrm{H}
$$
Hence, the correct answer is option: 'C'.