Q136 / 160 · AP EAMCET 2019 (21 Apr Shift 2) · Physics

A liquid of mass 250 g is kept warm in a vessel using an electric heater. The liquid is maintained at 57 °C when the power supplied by the heater is 30 W and surrounding temperature is 27 °C. As the heater is switched off, it took 10 s time for the temperature of the liquid to fall from 47 °C to 46.9 °C. The specific heat capacity of the liquid is

  • Correct answer
    A
    8000 J kg-1 K-1
  • B
    9000 J kg-1 K-1
  • C
    6000 J kg-1 K-1
  • D
    12000 J kg-1 K-1

Solution

The expression for the rate of heat flow is,

dqdt=-kT-T0

Here T0=Surrounding temperature

From first condition-|

30=-k57-27

⇒  k=-1

Using second condition-

dqdt=-kT-T0

but dqdt=msdTdt

∴  msdTdt=-k T-T0

Substitute the given values in the above equation.

2501000s47-46.910=--1 47-27

⇒  s=8000 J kg-1 K-1

Hence, the correct answer is option: 'A'.

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