A line meets the circle $x^2+y^2-4 x-4 y-8=0$ in two points A and B. If $\mathrm{P}(2,-2)$ is a point on the circle such that $\mathrm{PA}=\mathrm{PB}=2$ then the equation of the line AB is

• A

  $2 x+3 y=0$
• B

  $3 x+2 y=0$
• C

  $2 x+3=0$
• Correct answer
  D

  $2 y+3=0$

Hence, the correct answer is option: 'D'.