Q53 / 150 · MHT CET 2026 (19 April Shift 1) · Mathematics
A line making equal intercepts on coordinate axes and is tangent to the circle $x^2 + y^2 = 4$. The length of each intercept made by line on the coordinate axes is ...
- A$\sqrt{2}$
- B$2$
- Correct answerC$2\sqrt{2}$
- D$4$
Solution
Let the equation of the line making equal intercepts on the coordinate axes be $\dfrac{x}{a} + \dfrac{y}{a} = 1$.
This can be written as $x + y - a = 0$.
The line is tangent to the circle $x^2 + y^2 = 4$.
The center of the circle is $(0, 0)$ and its radius is $2$.
For a line to be tangent to a circle, the perpendicular distance from the center of the circle to the line must be equal to the radius.
$\dfrac{|0 + 0 - a|}{\sqrt{1^2 + 1^2}} = 2$
$\dfrac{|a|}{\sqrt{2}} = 2$
$|a| = 2\sqrt{2}$
The length of each intercept made by the line on the coordinate axes is $2\sqrt{2}$.
This can be written as $x + y - a = 0$.
The line is tangent to the circle $x^2 + y^2 = 4$.
The center of the circle is $(0, 0)$ and its radius is $2$.
For a line to be tangent to a circle, the perpendicular distance from the center of the circle to the line must be equal to the radius.
$\dfrac{|0 + 0 - a|}{\sqrt{1^2 + 1^2}} = 2$
$\dfrac{|a|}{\sqrt{2}} = 2$
$|a| = 2\sqrt{2}$
The length of each intercept made by the line on the coordinate axes is $2\sqrt{2}$.
Hence, the correct answer is option: 'C'.