Q142 / 160 · TS EAMCET 2022 (19 Jul Shift 1) · Physics
A light ray travels from a medium with refractive index $\mathrm{n}_1$ to another medium of refractive index $\mathrm{n}_2$. If $\mathrm{n}_1=2$ and $\mathrm{n}_2=\sqrt{3}$, then find the critical angle.
- A$15^{\circ}$
- B$30^{\circ}$
- C$45^{\circ}$
- Correct answerD$60^{\circ}$
Solution
Critical angle is defined by
$$
\begin{aligned}
& \sin \theta_{\mathrm{c}}=\frac{\mathrm{n}_2}{\mathrm{n}_1} \\
& \sin \theta_{\mathrm{c}}=\frac{\sqrt{3}}{2} \\
& \sin \theta_{\mathrm{c}}=\sin 60^{\circ} \\
& \theta_{\mathrm{c}}=60^{\circ}
\end{aligned}
$$
Hence, the correct answer is option: 'D'.