A light ray falls on a glass surface of refractive index √3, at an angle 60°. The angle between the refracted and reflected rays would be:

Correct answer: (B) 90°. From Snell's law, μ_1sini=μ_2sinr ⇒1×sin60°=√3sinr ⇒ r=30° Angle between the refracted say and reflected say is θ=180°-i+r=90°

Q138 / 200 · NEET 2022 (Phase 1) · Physics

A light ray falls on a glass surface of refractive index $\sqrt{3}$ , at an angle $60 °$ . The angle between the refracted and reflected rays would be:

A
$60 °$
Correct answer
B
$90 °$
C
$120 °$
D
$30 °$

Solution

From Snell's law,

$μ_{1} \sin i = μ_{2} \sin r$

$\Rightarrow 1 \times \sin 60 ° = \sqrt{3} \sin r$

$\Rightarrow r = 30 °$

Angle between the refracted say and reflected say is

$θ = 180 ° - (i + r) = 90 °$

Hence, the correct answer is option: 'B'.

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A light ray falls on a glass surface of refractive index 3, at an angle 60°. The angle between the refracted and reflected rays would be:

Solution

Relevant Questions

A light ray falls on a glass surface of refractive index $\sqrt{3}$ , at an angle $60 °$ . The angle between the refracted and reflected rays would be: