Q144 / 150 · MHT CET 2019 (Shift 2) · Physics

A lift is tied with thick iron ropes having mass ‘M’. The maximum acceleration of the lift is ‘a’ m/s2 and maximum safe stress is ‘S’ N/m2 . The minimum diameter of the rope is

  • A
    6Mg+aπS12
  • Correct answer
    B
    4Mg+aπS12
  • C
    Mg+aπS12
  • D
    Mg-aπS12

Solution

The maximum stress produced in a rope is given by
σmax=ForceArea=Mgπr2
As the lift is accelerating with acceleration a, then
σmax=Mg±aπr2
⇒r2=Mg±aπS [Given, σmax=S]
d24=Mg±aπS∵r=d2
⇒d=4Mg±aπS
As acceleration is maximum i.e.’=g +a, so
d=4Mg+aπS

Hence, the correct answer is option: 'B'.

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