A lead bullet strikes a target with a velocity of 480 ms^(-1). After the impact, the bullet falls dead and the heat produced in the process gets…

Question

A lead bullet strikes a target with a velocity of 480 ms^(-1). After the impact, the bullet falls dead and the heat produced in the process gets equally shared between the bullet and the target. If the specific heat capacity of lead is c=0.03 cal/g/°C, then the rise in temperature of the bullet is

MARKS Content Team · Accepted Answer

Correct answer: (B) 457℃. ∆Q=1/2K.E.⇒mc∆T=1/21/2m v^2J ∆T=(v^2)/4Jc= (480×480)/(4×4.2×(0.03×10^3))=457℃

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A lead bullet strikes a target with a velocity of 480 ms-1. After the impact, the bullet falls dead and the heat produced in the process gets equally shared between the bullet and the target. If the specific heat capacity of lead is c=0.03 cal/g/°C, then the rise in temperature of the bullet is

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