A large box is moving on a horizontal floor with constant acceleration a=g. A particle is projected inside the box with velocity u and angle θ with…

Question

A large box is moving on a horizontal floor with constant acceleration a=g. A particle is projected inside the box with velocity u and angle θ with horizontal from box frame. For the given u the value of θ for which horizontal range inside the box will be maximum is

MARKS Content Team · Accepted Answer

Correct answer: (B) (π)/8. T= (2u sinθ)/g R= (u^2 sin2θ)/g–(2u^2 sin^2θ)/g R will be maximum when dR/(dθ)=0 ⇒(2u^2)/g cos2θ−(2u^2)/g .2sinθ cosθ=0 ⇒2cos2θ=4sinθcosθ ⇒cos2θ=sin2θ ⇒2θ=(π)/4 ⇒θ=(π)/8

A large box is moving on a horizontal floor with constant acceleration $a = g$ . A particle is projected inside the box with velocity u and angle $θ$ with horizontal from box frame. For the given $u$ the value of $θ$ for which horizontal range inside the box will be maximum is

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