Q118 / 180 · JIPMER 2017 · Physics

A graph between pressure $P$ (along $y$-axis) and absolute temperature, $T$ (along $x$-axis) for equal moles of two gases has been drawn. Given that volume of second gas is more than volume of first gas. Which of the following statement is correct?

  • A
    Slope of gas 1 is less than gas 2
  • Correct answer
    B
    Slope of gas 1 is more than gas 2
  • C
    Both have some slopes
  • D
    None of the above

Solution

According to ideal gas equation, $p V=n R T$ or $\frac{p}{T}=\frac{n R}{V}, \frac{p}{T}$ represents slope of the graph As the number of moles are the same for the two gases, $\begin{aligned} & \therefore \quad \frac{p}{T} \propto \frac{1}{V} \\ & \because \quad V_2 \gt V_1 \text { (Given) } \\ & \therefore \quad(\text { Slope })_2 \lt (\text { Slope })_1 \\ & \text { or } \quad(\text { Slope })_1 \gt (\text { Slope })_2 \\ & \end{aligned}$

Hence, the correct answer is option: 'B'.

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