A galvanometer coil has a resistance $80 \Omega$ and current for full-scale deflection is 10 mA . A resistance of $920 \Omega$ is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is 0.2 V , the number of divisions on the scale is

Determining the number of divisions on the voltmeter scale requires calculating the maximum measurable voltage and relating it to the instrument's least count.

The voltmeter's total resistance is $R_{\text{total}} = R_g + R_s = 80\Omega + 920\Omega = 1000\Omega$.

The full-scale deflection voltage is $V_{\text{max}} = I_g \cdot R_{\text{total}} = 0.01\text{A} \cdot 1000\Omega = 10\text{V}$.

Since the least count is $0.2\text{V}$, the number of divisions is $N = \frac{10\text{V}}{0.2\text{V}} = 50$

$\boxed{50}$