A freshly prepared sample of a radioisotope of half-life 1386 s has activity 10^3 disintegrations per second. Given that In 2 = 0.693, the fraction of…

Question

A freshly prepared sample of a radioisotope of half-life 1386 s has activity 10^3 disintegrations per second. Given that In 2 = 0.693, the fraction of the initial number of nuclei (expressed in nearest integer percentage) that will decay in the first 80 s after preparation of the sample is

MARKS Content Team · Accepted Answer

Correct answer: 4. f = 1 - e^(- λ t) = 1 - e^(- λ t) ≈ 1 - 1 - λ t = λ t f = 0.04 Hence % decay ≈ 4 %

A freshly prepared sample of a radioisotope of half-life 1386 s has activity ${10}^{3}$ disintegrations per second. Given that In 2 = 0.693, the fraction of the initial number of nuclei (expressed in nearest integer percentage) that will decay in the first 80 s after preparation of the sample is

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