Q174 / 200 · Manipal (MET) 2011 · Physics

A force of 10 N acts on a body of mass 20 kg for 10 s . Change in its momentum is

  • A
    $5 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
  • Correct answer
    B
    $100 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
  • C
    $200 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
  • D
    $1000 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

Solution

$d p=F \times d t$ $=10 \times 10=100 \mathrm{~kg}\mathrm{m} / \mathrm{s}$

Hence, the correct answer is option: 'B'.

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