A force F=i-5i^-7j^+3k^ acting on a particle causes a displacement s=3i^+2j^+ak in its own direction. If the work done is 14 J, then the value of ‘a’…

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A force F=i-5i^-7j^+3k^ acting on a particle causes a displacement s=3i^+2j^+ak in its own direction. If the work done is 14 J, then the value of ‘a’ is

MARKS Content Team · Accepted Answer

Correct answer: (B) 5. Given, F=-5i^-7j^+3k^, s=3i-2j^+ak^ And W=F.s …. (i) Substituting above values in Eq. (i), we get 14=-5i^-7j^+3k^.3i^-2j^+ak^ ⇒14=-15+14+3a ⇒a=15/3=5

A force $(F) = i - 5 \hat{i} - 7 \hat{j} + 3 \hat{k}$ acting on a particle causes a displacement $(s) = 3 \hat{i} + 2 \hat{j} + a k$ in its own direction. If the work done is 14 J, then the value of ‘a’ is

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