A force $\overrightarrow{\mathrm{F}}$, acting on an electric charge $q$, in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity $\vec{v}$. Then $\overrightarrow{\mathrm{F}}$ is equal to (where $\vec{E}$ and $\vec{B}$ are electric field and magnetic field respectively)

• Correct answer
  A

  $q \overrightarrow{\mathrm{E}}$
• B

  $q(\vec{v} \times \overrightarrow{\mathrm{B}})$
• C

  $q(\vec{v} \times \overrightarrow{\mathrm{E}})$
• D

  $q \overrightarrow{\mathrm{~B}}$

Hence, the correct answer is option: 'A'.