Q80 / 180 · KCET 2018 · Mathematics
A flashlight has \( 10 \) batteries out of which \( 4 \) are dead. If \( 3 \) batteries are selected without
replacement andtested, then the probability that all \( 3 \) are dead is
replacement andtested, then the probability that all \( 3 \) are dead is
- Correct answerA\( \frac{1}{30} \)
- B\( \frac{2}{8} \)
- C\( \frac{1}{15} \)
- D\( \frac{1}{10} \)
Solution
Total number of batteries are 10
Number of dead batteries is 4
So, P(all three dead)
$=\frac{4}{10} \times \frac{3}{9} \times \frac{2}{8}=\frac{1}{30}$
Hence, the correct answer is option: 'A'.