A fighter plane of length 20 m, wing span (distance from tip of one wing to the tip of the other wing) of 15 m and height 5 m is flying towards east over Delhi. Its speed is $240 m{s}^{-1}.$ The earth's magnetic field over Delhi is $5\times {10}^{-5}T$ with the declination angle $~0^o$ and dip of $\theta$ such that $\sin \theta =\frac{2}{3}.$If the voltage developed is $V_B$ between the lower and upper side of the plane and $V_W$ between the tips of the wings then $V_B and V_W$ are close to :

• A

  $V_B=\mathrm{40 }mV;V_W=135 mV$ with left side of pilot at higher voltage
• B

  $V_B=45 mV;V_W=120 mV$ with right side of pilot at higher voltage
• C

  $V_B=40 mV;V_W=135 mV$ with right side of pilot at high voltage
• Correct answer
  D

  $V_B=45 mV;V_W=120 mV$ with left side of pilot at higher voltage

Hence, the correct answer is option: 'D'.