A door of mass $M$ and width $L$ is hinged at one end and rotates about a vertical axis without friction. A bullet of mass $m(m \ll M)$ fired perpendicularly to the door at a speed $v$ gets embedded in it at a distance $x$ from its axis of rotation. Assuming the door was stationary initially, how does the resultant angular speed $\omega$ of the door vary as a function of $x$ ?

• Correct answer
  A

  
  
• B

  
  
• C

  
  
• D

  
  

Hence, the correct answer is option: 'A'.