Q97 / 180 · AIIMS 2019 (26 May) · Physics
A disc of radius $2 \mathrm{~m}$ is rotating with angular is to be put on the disc. Friction coefficient between disc and block is $\mu_{\mathrm{K}}=0.3$, then find the maximum distance from axis where the block can be placed without sliding
- A$2 \mathrm{~cm}$
- Correct answerB$3 \mathrm{~cm}$
- C$4 \mathrm{~cm}$
- D$6 \mathrm{~cm}$
Solution
$\begin{aligned} & \text { Friction force }=\text { centripetal force } \mu_{\mathrm{K}}(m g) \\ & =m \omega^2 x \\ & \mu_{\mathrm{K}} \cdot g=\omega^2 x \\ & 0.3 \times 10=(10)^2 x \Rightarrow x=\frac{3}{100} \mathrm{~m}=3 \mathrm{~cm}\end{aligned}$
Hence, the correct answer is option: 'B'.