Q29 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

A diode AM detector with the output circuit consisting of R=1 kW and C=1 μF would be more suitable for detecting a carrier signal of

  • A
    0.1 kHz
  • B
    0.5 kHz
  • C
    1 kHz
  • Correct answer
    D
    10 kHz

Solution

Given R=1 kΩ or R=1×103 Ω and C=1 μF or C=1×10-6 F.

In this condition, frequency of carrier signal,

1RC<<fc

11×103×10-6<<fc

∴fc>>1 kHz

Since, frequency must be greater than 1 kHz the possible answer will be fc=10 kHz.

Hence, the correct answer is option: 'D'.

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