A die is thrown $(2 n+1)$ times. The probability of getting 1 or 3 or 4 atmost $n$ times on it is

• A

  $\frac{1}{n}$
• B

  $\frac{1}{2 n+1}$
• C

  $\frac{n}{2 n+4}$
• Correct answer
  D

  $\frac{1}{2}$

Hence, the correct answer is option: 'D'.