A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the…

Question

A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0°C will be (Given gas constant R=8.3 J K^(-1) mol^(-1))

MARKS Content Team · Accepted Answer

Correct answer: (C) 498 J. At STP volume occupied by one mole of a gas is 22.4 L. Therefore, number of moles are, n=44.8/22.4=2 mol. The process is isochoric process as the volume of the cylinder remains fixed and helium is a monatomic gas. Therefore, amount of heat needed will be, Q=nCvΔT=23/2R20=3×8.3×20=498 J

A cylinder of fixed capacity of $44.8$ litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by $20.0 ° C$ will be (Given gas constant $R = 8.3 J K^{- 1} {mol}^{- 1}$ )

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Relevant Questions

A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0°C will be (Given gas constant R=8.3 J K-1 mol-1)

Solution

Relevant Questions

A cylinder of fixed capacity of $44.8$ litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by $20.0 ° C$ will be (Given gas constant $R = 8.3 J K^{- 1} {mol}^{- 1}$ )