A cyclist riding the bicycle at a speed of $14\sqrt{3} \mathrm{m }{\mathrm{s}}^{-1}$ takes a turn around a circular road of radius $20\sqrt{3} \mathrm{m}$ without skidding. Given $g=\mathrm{9.8 }\mathrm{m }{\mathrm{s}}^{-2}$ What is his inclination to the vertical ?

• A

  $30°$
• B

  $90°$
• C

  ${45}^{\mathrm{o}}$
• Correct answer
  D

  $60°$

Hence, the correct answer is option: 'D'.