A current of 2 ~A flows in an electric circuit as shown in figure. The potential difference (V_R-V_S ) , in volts (V_R . and V_S are potentials at R and S respectively) is

Correct answer: (C) +4. Current through each arm P R Q and P S Q=1 ~A V_P-V_R=3 ~V V_P-V_S=7 ~V From Eqs. (i) and (ii), we get V_R-V_S=+4 ~V

Q151 / 160 · AP EAMCET 2008 · Physics

A current of $2 \mathrm{~A}$ flows in an electric circuit as shown in figure. The potential difference $\left(V_R-V_S\right)$, in volts $\left(V_R\right.$ and $V_S$ are potentials at $R$ and $S$ respectively) is

A
$-4$
B
$+2$
Correct answer
C
$+4$
D
$-2$

Solution

Current through each arm $$ \begin{gathered} P R Q \text { and } P S Q=1 \mathrm{~A} \\ V_P-V_R=3 \mathrm{~V} \\ V_P-V_S=7 \mathrm{~V} \end{gathered} $$ From Eqs. (i) and (ii), we get $$ V_R-V_S=+4 \mathrm{~V} $$

Hence, the correct answer is option: 'C'.

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