A current of $5 \mathrm{A}$ is passing through a non-linear magnesium wire of cross-section $0.04{ \mathrm{m}}^2$. At every point the direction of current density is at an angle of $60°$ with the unit vector of area of cross-section.
The magnitude of electric field at every point of the conductor is: (resistivity of magnesium $\rho =44\times {10}^{-8} \mathrm{\Omega m}$)

• A

  $11\times {10}^{-2} \mathrm{V} {\mathrm{m}}^{-1}$
• B

  $11\times {10}^{-7} \mathrm{V} {\mathrm{m}}^{-1}$
• Correct answer
  C

  $11\times {10}^{-5} \mathrm{V} {\mathrm{m}}^{-1}$
• D

  $11\times {10}^{-3} \mathrm{V} {\mathrm{m}}^{-1}$

Hence, the correct answer is option: 'C'.