A cubic structure is formed where atoms of element $X$ are occupied at corner of cube and also at face centers. Atoms of element $Y$ are present at body center and at the edge centers. If all the atoms are removed along a plane passing through the middle of the cube (bisecting the four edges), the formula will become

• A

  $X Y_2$
• B

  $X_4 Y_3$
• Correct answer
  C

  $X Y$
• D

  $X_2 Y_3$

Solution

- $=X$, at corners (cor) and face centre (fc) $\mathbf{-}=Y$, at edge centre $(\mathrm{ec})$ and body centre $(\mathrm{bc})$ After removal, number of atoms ratio in the crystal,
So, formula of the crystal will be $X Y$.

Hence, the correct answer is option: 'C'.