Q64 / 90 · JEE Main 2021 (01 Sep Shift 2) · Physics

A cube is placed inside an electric field, E→=150y2j^ The side of the cube is 0.5 m and is placed in the field as shown in the given figure. The charge inside the cube is:

Figure

  • Correct answer
    A
    8.3×10-11C
  • B
    3.8×10-11C
  • C
    3.8×10-12C
  • D
    8.3×10-12C

Solution

Figure

By gauss law ∮E→·ds→=qin ε0

ε0(150)(0.5)2×(0.5)2=qin

qin=8.85×10-12×15016=8.3×10-11C

Hence, the correct answer is option: 'A'.

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