Q38 / 120 · VITEEE 2019 · Chemistry
A coordination complex compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution; on reacting with excess of $\mathrm{AgNO}_{3}, \mathrm{AgCl}$ is precipitated. The ionic formula for this complex would be:
- Correct answerA$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\left(\mathrm{NO}_{2}\right)\right] \mathrm{Cl}_{2}$
- B$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right]\left[\mathrm{Cl}\left(\mathrm{NO}_{2}\right)\right]$
- C$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right) \mathrm{Cl}\right]\left[\left(\mathrm{NH}_{3}\right) \mathrm{Cl}\right]$
- D$\left.\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\right]\left[\mathrm{NO}_{2}\right)_{2} \mathrm{Cl}_{2}\right]$
Solution
The most probable complex which gives three mole ions in aqueous solution may be $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}$.
Hence, the correct answer is option: 'A'.