A container of volume $2.24 \text{L}$can with stand a maximum pressure of $2$ atm at $298 \text{K}$ before exploding. The maximum amount of nitrogen (in $\text{g}$) that can be safely put in this container at this temperature is closest to

From ideal gas equation $\text{p} \text{V}=\text{n} \text{R} \text{T}$

maximum number of moles in container,

$\text{n}=\frac{\text{p}\text{V}}{\text{R}\text{T}}=\frac{2\times 2.24}{0.0821\times 298}$

$=0.18$ moles Maximum weight of ${\text{N}}_2$ in container
$=0183\times 28=5.127 \text{g}$

At $5.127 \text{g}$ exploding can occur. Thus, it must be less than $5.127$ . Thus, the maximum amount of nitrogen that can be safely put in this container at $298$ temperature and exert pressure less than $2$atm will be closest to undefined.