Q196 / 200 · Manipal (MET) 2010 · Physics
A constant torque acting on a uniform circular wheel changes its angular momentum from $A_0$ to $4 A_0$ in 4 s . The magnitude of this torque is
- Correct answerA$\frac{3 A_0}{4}$
- B$A_0$
- C$4 A_0$
- D$12 A_0$
Solution
Torque $\vec{\tau}=\frac{\overrightarrow{\mathrm{dL}}}{d t}=\frac{L_2-L_1}{\Delta t}=\frac{4 A_0-A_0}{4}=\frac{3 A_0}{4}$
Hence, the correct answer is option: 'A'.