Q128 / 155 · WBJEE 2019 · Physics

A compressive force is applied to a uniform rod of rectangular cross-section so that its length decreases by $1 \%$. If the Poisson's ratio for the material of the rod be $0.2,$ which of the following statements is correct? "The volume approximately ...........

  • A
    decreases by $1 \%$
  • B
    decreases by $0.8 \%$
  • Correct answer
    C
    decreases by $0.6 \%$
  • D
    increases by $0.2 \%$

Solution

Given, Decrement in the length $=1 \%$ Poisson's ratio for material of the rod, $\sigma=0.2$ As we know that, Volume, $v=\pi r^{2} l,[$ where $, l$ is the length of the rod $]$ $$ \frac{\Delta V}{V}=\frac{2 \Delta r}{r}+\frac{\Delta l}{l}...(i) $$ since, Poisson's ratio, $\sigma=\frac{-\Delta D / D}{\Delta L / L}$ $$ =\frac{-\Delta r / r}{\Delta L / L} $$ So, Eq. (i) can be written as, $$ \begin{aligned} \frac{\Delta V}{V}=\frac{\Delta l}{l}(1-2 \sigma) \\ \frac{\Delta V}{V} \times 100 &=\left(\frac{\Delta l}{l} \times 100\right) \times(1-2 \sigma) \\ &=-1 \times[1-2 \times(0.2)] \\ &=-1 \times[1-0.4] \\ &=-0.6 \% \end{aligned} $$ Here, negative sign shows the decrement in the volume.

Hence, the correct answer is option: 'C'.

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