Q6 / 60 · JEE Advanced 2012 (Paper 1) · Chemistry
A compound $\mathrm{M}_{\mathrm{p}} \mathrm{X}_{\mathrm{q}}$ has cubic close packing (ccp) arrangement of $\mathrm{X}$. Its unit cell structure is shown below. The empirical formula of the compound is


- A$\mathrm{MX}$
- Correct answerB$\mathrm{MX}_{2}$
- C$\mathrm{M}_{2} \mathrm{X}$
- D$\mathrm{M}_{5} \mathrm{X}_{14}$
Solution
No. of $M$ atoms $=\frac{1}{4} \times 4+1=1+1=2$
No. of $X$ atoms $=\frac{1}{2} \times 6+\frac{1}{8} \times 8=3+1=4$
So, formula $=M_{2} X_{4}=M X_{2}$
Hence, the correct answer is option: 'B'.