Q14 / 68 · NTA Abhyas (JEE Main) 2020 · Physics · Electromagnetic Induction

A coil of inductive reactance 3 1  Ω  has a resistance of 8  Ω . It is placed in series with a condenser of capacitive reactance 2 5  Ω . The combination is connected to an ac source of 110 V . The power factor of the circuit is

  • A
    0.33
  • B
    0.56
  • C
    0.64
  • Correct answer
    D
    0.80

Solution

X L = 3 1  Ω ,   X C = 2 5  Ω ,   R = 8  Ω

Impedance of series LCR is

Z = R 2 + X L - X C 2

   = 8 2 + 3 1 - 2 5 2 = 6 4 + 3 6 = 1 0  Ω

Power factor, cos ϕ = R Z = 8 1 0 = 0.8

Hence, the correct answer is option: 'D'.

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