A coil of 40 henry inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is

Correct answer: (B) 5 seconds. Time constant is L / R Given, L=40 H \ R=8 Ω ∴ τ=40 / 8=5 sec .

Q82 / 120 · VITEEE 2018 · Physics

A coil of 40 henry inductance is connected in series with a resistance of $8 \mathrm{ohm}$ and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is

Time constant is $\mathrm{L} / \mathrm{R}$ Given, $L=40 \mathrm{H} \& \mathrm{R}=8 \Omega$ $\therefore \tau=40 / 8=5 \mathrm{sec} .$

Hence, the correct answer is option: 'B'.