Q21 / 117 · NTA Abhyas (JEE Main) 2020 · Physics · Waves and Sound

A closed and an open organ pipe have the same length. When they are vibrating simultaneously in their first overtone, they produce three beats. The length of the open pipe is now made one third the original length and one of its ends is closed. On the other hand, the length of the closed pipe is made three times the original length. The number of beats produced when they vibrate with fundamental frequencies will be

  • Correct answer
    A
    8
  • B
    14
  • C
    17
  • D
    8

Solution

V= speed of sound and L= lenght of pipes

For open pipe first overtone f1=VL

For closed pipe first overtone f'1=3V4L

∴   f1−f'1=VL−3V4L=3

∴   V4L=3

∴   VL=12 

When we close one end of the open pipe and make its length one-third of the original length, then its fundamental frequency is

f=V4(L3)=3V4L

When the length of closed pipe is made 3 times, the fundamental frequency is

f'=V4(3L)=V12L

Beats produced =f-f'

=3V4L-V12L

=812.VL=812×12

=8

Hence, the correct answer is option: 'A'.

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