Q60 / 75 · JEE Main 2020 (04 Sep Shift 2) · Physics

A circular coil has moment of inertia 0.8 kg m2 around any diameter and is carrying current to produce a magnetic moment of  20 Am2. The coil is kept initially in a vertical position and it can rotate freely around a horizontal diameter. When a uniform magnetic field of 4 T is applied along the vertical, it starts rotating around its horizontal diameter. The angular speed the coil acquires after rotating by 60o will be :

  • Correct answer
    A
    10 rad s-1
  • B
    10π rad s-1
  • C
    20π rad s-1
  • D
    20 rad s-1

Solution

From energy conservation 

12Iω2=Un-Ut

   =-MBcos60°-(-MB)

MB2=12Iω2

20×42=12(08)m2

100=ω2

ω=10rad 

Hence, the correct answer is option: 'A'.

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