Q155 / 155 · WBJEE 2020 · Physics
A charged particle moves with constant velocity in a region where no effect of gravity is felt but an electrostatic field $\overrightarrow{\mathrm{E}}$
together with a magnetic field $\vec{B}$ may be present. Then which of the following cases are possible?
- Correct answerA$\vec{E} \neq 0, \vec{B} \neq 0$
- B$\vec{E} \neq 0, \vec{B}=0$
- Correct answerC$\vec{E}=0, \vec{B}=0$
- Correct answerD$\overrightarrow{\mathrm{E}}=0, \overrightarrow{\mathrm{B}} \neq 0$
Solution
If a charged particle is moving in a gravity-free space without changing its velocity, then three cases possible
(i) Particle can move with constant velocity in any direction, if \(\vec{E}=0, \vec{B}=0\).
(ii) If \(\vec{E}, \vec{B}\) are having values such that \(q E=q v B\) and hence both forces (Force due to magnetic field and force due to electric field) acts in such a way that they cancel each other, in this case also particle can move with uniform velocity.
(iii) If \(\vec{E}=0, \vec{B} \neq 0\) and \(\vec{B}\) is such that it acts in the direction of velocity then magnetic force would be zero and hence velocity can remain constant.
Hence, the correct answer is options: 'A', 'C', 'D'.